SensorCatalog

Current transformer burden calculator

Add up the cable and the meters on a CT secondary and compare the total with the rated burden.

Current transformer

Rated secondary current

Cable and devices

Result

6.66VA

The secondary circuit takes 133 % of the 5 VA rated burden. Above the rated burden: the accuracy class is not guaranteed. Most of the burden is cable: a 1 A secondary has 25 times less cable burden.

Cable resistance
0.2064 Ω15 m × 2 conductors, 20 °C
Cable burden
5.16 VAat 5 A
Device burden
1.5 VAas entered
Total burden
6.66 VA133 % of 5 VA
Secondary impedance
0.2664 Ω1.332 V at rated current
Longest cable
10.17 mone way, at the rated burden
Factor at actual burden
—enter Rct and the rated factor
Cable burden on the other secondary
0.2064 VAwith a 1 A secondary

Schematic

CTS1S25 A0.206 Ω0.206 Ω15 m2.5 mm²Devices1.5 VATotal 6.66 VA
Drawn from the inputs above; not to scale.
Formulas and standards
S = Isn² × (2 ρ L / A) + Sdevices
ALF' = ALF × (Rct + Rrated) / (Rct + Ractual),   R = S / Isn²

The burden of a current transformer is the apparent power its secondary circuit takes at rated secondary current, I² × Z. The two cable conductors add 2 × ρ × L / A, with copper's resistivity corrected for the conductor temperature; meters and relays add the burden stated on their datasheets. The calculator adds cable and devices arithmetically, as resistances, which overstates the total slightly when the devices are inductive.

IEC 61869-2 specifies the ratio and phase error of a measuring class between 25 % and 100 % of the rated burden; the CT's datasheet states the exact range. An overburdened CT reads low and saturates earlier. For protection cores and the instrument security factor the usual approximation is ALF' = ALF × (Rct + Rrated) / (Rct + Ractual): a lighter burden raises the factor, which matters for meters that should be protected from fault currents.

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How the current transformer burden calculator works

A current transformer reproduces the primary current at a smaller secondary current, 1 A or 5 A, and drives it through whatever is connected: the cable to the panel and the meters, relays or transducers at the end. That circuit is the burden, stated in volt-amperes at rated secondary current. A CT keeps its accuracy class only while the burden stays within its rated range.

The calculator adds the burden of the two cable conductors, I² × 2 ρ L / A with copper’s resistance at the conductor temperature, to the devices’ burden, and compares the total with the CT’s rated burden. It also gives the longest cable for the rated burden and the accuracy limit factor under the actual burden.

Why cable is the usual problem

At 5 A every ohm in the secondary circuit costs 25 VA. Twenty metres of 2.5 mm² copper there and back is 0.275 Ω, or 6.9 VA, more than a typical 5 VA CT can carry before any meter is connected. With a 1 A secondary the same cable is 0.28 VA. This is why CTs with long cable runs, from switchgear to a remote panel, normally use 1 A secondaries, and why 5 A secondaries stay close to their meters.

The 25 to 100 % range

IEC 61869-2 specifies the ratio and phase error of measuring classes such as 0.2, 0.5 and 1 for secondary burdens between 25 % and 100 % of the rated burden. Above it the CT reads low and saturates earlier; below it the error is not covered by the class and may exceed it. Modern electronic meters take a fraction of a volt-ampere, so an oversized rated burden can leave a CT below 25 % with the cable alone. The datasheet states the range a particular CT is specified for.

Accuracy limit and security factor

Protection CTs have an accuracy limit factor, ALF, the multiple of rated current up to which the composite error stays within the class. Measuring CTs have an instrument security factor, FS, which limits how much current reaches the meter during a fault. Both depend on the actual burden: the usual approximation is ALF’ = ALF × (Rct + Rrated) / (Rct + Ractual), where Rct is the secondary winding resistance. A light burden raises the factor, which helps a protection core but lets more fault current through to a meter.

For the voltage drop on cables powering field sensors, use the sensor supply voltage drop calculator; for measuring current with a resistor instead, the current shunt calculator.

Frequently asked questions

Can I add VA and ohms directly?

Convert first: R = VA / I². The calculator treats cable and devices as resistive and adds them arithmetically, which overstates the total slightly for inductive devices. That errs on the safe side.

Must the secondary never be opened?

Yes. An open secondary under load drives the CT into saturation and can produce dangerous voltages. Short the secondary terminals before disconnecting a meter.

Does the conductor temperature matter?

Copper’s resistance rises by 0.393 % per kelvin. A cable at 60 °C has 16 % more resistance than at 20 °C, and the same rise in cable burden.

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